Question: Solve: Tekz (1+kx) J da where k is a constant. If there are any particular values of k where your method doesn't work, compute those

Solve:

Tekz (1+kx) J da where k is a constant. If there are

 

Tekz (1+kx) J da where k is a constant. If there are any particular values of k where your method doesn't work, compute those antiderivatives separately.

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