Question: Solve the differential equation y (k+2) + 3y (k+1) + 2y (k) = u(k) where y (0) = 1, y(k)=0 for k
Solve the differential equation y (k+2) + 3y (k+1) + 2y (k) = u(k) where y (0) = 1, y(k)=0 for k
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