Question: Solve the equation 2x^2 y - 2xy' + 20 = 0. Solve the differential equation y - 4y' + 3y = e^3x (x +
Solve the equation 2x^2 y" - 2xy' + 20 = 0. Solve the differential equation y" - 4y' + 3y = e^3x (x + 1) Solve the equation x d^2y/ dx^2 = 2 [(dy/dx)^2 - dy dx] .
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