Solve the equations with the first condition shown and find the magnitude of the force F that will cause the table to start slipping. F=fill in blank N (to 2 decimal places) FBDs and Kinetics -dii: Foos 30" - FftA - Fte = mx (1) -dei: NA + No - mg - Fsm 30" = 0 (2) Moment - Fees 30%-1 + Fsun 30"-2 - (F+A+Ffs) 2 about? (about 2) -No *2 + No *2 = IG = 0 (7) } Count #unknowns: 6 (*, NA, No, FA, Fte, F) #equations 3 Additional equations F is large enough to cause slip to start! (4) Ff = MNAF =s No x=0 once table starts to slip, FF+=MxNA, Fre=Mens (s) (c) FA X ma G Ffe NB NA 2ft 2fe 3 F 29 fift 2f+ Given Desk of weight 75 lb and center of mass G Force F large enough to overcome static friction s = 0.5 and k = 0.2 30 1 ft G 20 2 ft- 20 B