solve the following and use the data given please

ws 2. (10 points) Apply AHP to re-compute the weights for the three values: Affordability, Quality, and Style in HW1 as the row averages of the pairwise comparison matrix. Compute Cl of the matrix; if it is greater than 0.05, then modify the matrix to make it totally consistent by making the least confident pairwise comparison be consistent with the other two comparisons. However, as an exercise, even if your matrix is sufficiently consistent, please follow the same process to make it totally consistent. With this totally consistent matrix, compute RWA1, the ratio of the largest to the smallest weights, and RWA2, the ratio of the largest to the second largest weights for AHP, and compare them respectively the ratios RWM1 and RWM2 from Multifactor Evaluation in HW1 to see whether the AHP ratios are greater, implying that the AHP weights are more differentiated than the weights that are generally less precisely assigned in HW1. 2 28 2e 27 28 HW2 Christopher A BA Q S co 8 6 7 4 Q 5 S 1 1/8 1/6 1.292 1 1/7 9.143 1 6 SUM 14 ws 2. (10 points) Apply AHP to re-compute the weights for the three values: Affordability, Quality, and Style in HW1 as the row averages of the pairwise comparison matrix. Compute Cl of the matrix; if it is greater than 0.05, then modify the matrix to make it totally consistent by making the least confident pairwise comparison be consistent with the other two comparisons. However, as an exercise, even if your matrix is sufficiently consistent, please follow the same process to make it totally consistent. With this totally consistent matrix, compute RWA1, the ratio of the largest to the smallest weights, and RWA2, the ratio of the largest to the second largest weights for AHP, and compare them respectively the ratios RWM1 and RWM2 from Multifactor Evaluation in HW1 to see whether the AHP ratios are greater, implying that the AHP weights are more differentiated than the weights that are generally less precisely assigned in HW1. 2 28 2e 27 28 HW2 Christopher A BA Q S co 8 6 7 4 Q 5 S 1 1/8 1/6 1.292 1 1/7 9.143 1 6 SUM 14