Solve the following for $x,$ using the quadratic formula:

$3x^2-2x=2$

$x=\frac{2}{3}$ and $x=0$

$x=\frac{1+-\sqrt[\phantom{2}]{7}}{3}$

No Real Solutions

$x=\frac{-2+-2\sqrt[\phantom{2}]{7}}{6}$

None of the above

Question $8(3$ points$)$

Convert the following:

$-{40}_{10}$