Question: Solve the following recurrence relations using the repeated substitution method: T(n) = T(n/2) + 1 when n 1, T(1) =1 T(n) = T(n/2) + n

Solve the following recurrence relations using the repeated substitution method: T(n) = T(n/2) + 1 when n 1, T(1) =1 T(n) = T(n/2) + n when n 1, T(1) =1 T(n) = T(n-1) + 1 when n 1, T(1) =1 T(n) = T(n-1) + n when n 1, T(1) =1 T(n) = 2T(n-1) + 1 when n 1, T(1) =1 T(n) = T(n-1) * n when n 1, T(1) =1

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