Solve the following Vector Calculus problem. Be sure to answer the entire question. Thank you!

3. (a) (20 pts) Consider the double iterated integral 1 - ry dady. Since the integrand is unbounded on the rectangle R = [0, 1] x [0, 1], the double integral is defined as the limit of double integrals over the rectangle [0, t] x [0, t] as t -+ 1-. This is called an improper integral which is very similar to improper inte- gral for one-variable functions.In short, you can forget about it being unbounded. Evaluate the double iterated integral by using the change of variables u - U and y = utv V2 V2 Remark: You may assume change of variables formula holds and that you can interchange the order of integration for improper integrals. Basically, treat it like any good old double integral. Hint: Use trig substitution and write your expression in arcsine functions don't use arctangent. Recall the relationship trigonometric identity from Pre-Calc or Calc 2 arctan(r) = arcsin 1+ x2 and arcsin(x) = arctan