Solve the given initial value problem and determine how the interval in which the solution exists depends on the initial value yo, for yo # 0. A. y(t) = B. y(t) C. y(t) D. y(t) E. None = = = V O D O A OB OE y' + y = 0, y (0) = Yo Yo the solution exists when t> ' 2yt+1 2y 2yt+1 Yo 2y+1 Yo 2yot+1 the solution exists when t> the solution exists when t> the solution exists when t> 2y 1 2y - 2y