Solve the initial value problem. $\frac{dy}{dx}=sin(5x+),$ when $x=0,y=3$

$y=-\frac{1}{5}cos(5x+)+\frac{14}{5}$

$y=-\frac{1}{5}cos(5x+)+3$

$y=5cos(5x+)+3$

$y=-cos(5x+)+2$