Question: Solve the initial - value problem displaystyle frac { d ^ 2 y } { dt ^ 2 } + 1 2

Solve the initial-value problem \displaystyle \frac{d^2y}{dt^2}+12\frac{dy}{dt}+36 y =0,\; y(1)=0,\; y'(1)=1.
Answer: y(t)=

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