Question: Solve the initial value problem dx dt with x(0) = -2. x(t): = - 4x = cos(2t) (1/10)(sin2t-2cos2t)-(9/5)(e^(4t)) (1 point) Find the general solution,

Solve the initial value problem dx dt with x(0) = -2. x(t):
( 1 point) Find the general solution, \( y(t) \), which solves the problem below, by the method of integrating factors.\[4

Solve the initial value problem dx dt with x(0) = -2. x(t): = - 4x = cos(2t) (1/10)(sin2t-2cos2t)-(9/5)(e^(4t)) (1 point) Find the general solution, y(t), which solves the problem below, by the method of integrating factors. dy 4t +y=t dt Find the integrating factor, u(t): = e**((Int)/5) and then find y(t): ((t**7/9))+(C/(t**(1/4))) the unkown constant.) . (use C as

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