Solve the initial value problem.

$,y^{\text{'}\text{'}}+0\mathrm{.}4y^{\text{'}}+0\mathrm{.}4y=5\mathrm{.}44e^{0\mathrm{.}8x},y(0)=4\mathrm{.}4,y^{\text{'}}(0)=2\mathrm{.}52$

$y(x)=$