Question: Solve the initial value problem yy'x=x2y22 with y(2)=-322.To solve this, we should use the substitutionu= help (formulas)u'= help (formulas)Enter derivatives using prime notation (e.g., you

Solve the initial value problem yy'x=x2y22 with y(2)=-322.To solve this, we should use the substitutionu= help (formulas)u'= help (formulas)Enter derivatives using prime notation (e.g., you would enter y' for dyd).After the substitution above, we obtain the following linear differential equation in x,u,u'. help (equations)The solution to the original initial value problem is described by the following equation in x,y. help (equations)

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