Question: Solve the initial value problem yy'+x=x2+y22 with y(3)=-402.a.To solve this, we should use the substitutionu=u'=b. After the substitution from the previous part, we obtain the

Solve the initial value problem yy'+x=x2+y22 with y(3)=-402.a.To solve this, we should use the substitutionu=u'=b. After the substitution from the previous part, we obtain the following linear differential equation inx,u,u'.c. The solution to the original initial value problem is described by the following equation inx,y.

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