Question: Solve the linear differential equation x^2y' + x (x + 2) y = e^x; y (1) = 1 by finding the integrating factor. [Note: This

Solve the linear differential equation x^2y' + x (x + 2) y = e^x; y (1) = 1 by finding the integrating factor. [Note: This is known as initial value problem]

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