Solve the problem.

A rectangular field is to be enclosed on four sides with a fence. Fencing costs $$2$ per foot for two opposite sides, and $$7$ per foot for the other two sides. Find the dimensions of the field of area $610f{t}^2$ that would be the cheapest to enclose.

$13\mathrm{.}2$ fe $52$ by $46\mathrm{.}2$ fie $57$

$46\mathrm{.}2$ ft e $$2$ by $13\mathrm{.}2$ ft e $$7$

$7\mathrm{.}1$ ft e $$2$ by $85\mathrm{.}4$ ft e $$7$

$86\mathrm{.}4$ ft e $$2$ by $7\mathrm{.}1$ ft e $$7$