Question: solve the question again with these changes: - type: W3 - handicap: 10% Individual establishment employs 200 persons. It is indicated that one parking space

solve the question again with these changes:

- type: W3

- handicap: 10%

solve the question again with these changes: - type: W3 - handicap:10% Individual establishment employs 200 persons. It is indicated that one parkingspace must be provided for every two employees and that (40\%) ofcars are compact cars. Also it is required (5\%) of the spacesshould be allocated for the disabled. The available parking lot space is

Individual establishment employs 200 persons. It is indicated that one parking space must be provided for every two employees and that (40\%) of cars are compact cars. Also it is required (5\%) of the spaces should be allocated for the disabled. The available parking lot space is (180ft wide x 200ft deep). Determine the best layout and assuming no walls and no walking edge. Initial Data 1) Parking required =200/2=100 parks 2) Parking Small Cars =40 parks, however assume, 30 parks can be imposed due to the possibility of standing in other places. 3) Impose unit section type module configuration: [Parking lot contains three double units sectional rows (one unit for small cars (2 raws) and two units for standard cars ( 4 raws)). 4) From the table of parking dimension, for angle 90\%: Small cars of stall width (SW=8) the module width (57'-2 ') and Standard cars of stall width (SW=8.5), the module width (660). 5) Total width =2(66)+1(572)=1892 6) Comparing the parking depth of 189'-2" with space (SW=8)=(180/8)2=44>30 8) Calculate the number of parks for standard cars (SW=8.5)=(180/8.5)22=84>70 9) Suppose handicapped parking (5) width (SW=12) in the first row for standard cars, the number of parks in the first row becomes =(180125)/8.5=14 parks 10) Suppose maneuver movement distance inside parking lot at the end of rows 2,3,4 width (SW=15), the number of parks in rows 2,3,4 become =(180152)/8.5=17 parks 11) The number of parks in the fifth row =(18060)/8=18 parks 12) The number of parks in the sixth row =180/8=22 parks 13) Summarizes the results and draws a diagram as follows: 2d-Parking Area Parking Dimensions for Each Car Group as a Function of Single and Double Loaded Module Options ANGLE OF PARK 2e-Parking Area Design Example Part One DEFINING REQUIREMENTS PW=SineSW

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