Question: Solve the question QUESTION 1 A random sample of 200 consumers showed that 120 consumers prefer brand A. Let PA = the true proportion of

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Solve the question QUESTION 1 A random sample of 200 consumers showedthat 120 consumers prefer brand A. Let PA = the true proportionof consumers preferring brand A. A 96% confidence interval for the true

QUESTION 1 A random sample of 200 consumers showed that 120 consumers prefer brand A. Let PA = the true proportion of consumers preferring brand A. A 96% confidence interval for the true proportion p of consumers preferring brand A is: A. (0.239, 0.945) O B. (0.529, 0.671) O C. (0.145, 0.598) O D. (0.045, 0.789) QUESTION 2 Find k such that P (k

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