Question: Solve the recurrence a n = 4a n-1 - 4a n-2 , n. 3; a 0 =1, a 1 =1 Solve the recurrence:a n =

  1. Solve the recurrence an= 4an-1 - 4an-2, n. 3; a0=1, a1=1
  2. Solve the recurrence:an= 3an-1 + (2n-5), n 1, a0=1
  3. Solve the recurrence an= 2an-1+ 3, n 1 a0 = 1

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