Question: Solve the recurrence relation subject to the basis step. T(1) = 3 T(n) = T(n/2)+n for n >= 2, n = 2^m Solve the recurrence
Solve the recurrence relation subject to the basis step.
T(1) = 3 T(n) = T(n/2)+n for n >= 2, n = 2^m

Solve the recurrence relation subject to the basis step. T(1)=3T(n)=T(2n)+nforn2,n=2m
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