Question: Solve the recurrence relations: (1) T(n) = 3T(n/2) + n, n = 2 k , T(1) = 1 (2) T(n) = 4T(n/2) + n 3
Solve the recurrence relations:
(1) T(n) = 3T(n/2) + n, n = 2k, T(1) = 1
(2) T(n) = 4T(n/2) + n3, n = 2k, T(1) = 1
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