Question: Solve the system by back substitution. 11. 2x + 2y4z + w = -5 3y + 4z w = 0 2z - 7w =

Solve the system by back substitution. 11. 2x + 2y4z + w= -5 3y + 4z w = 0 2z - 7w =  

Solve the system by back substitution. 11. 2x + 2y4z + w = -5 3y + 4z w = 0 2z - 7w = -6 5w = 15 -

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