Solve the system of equations by any method. 3:6 431+ 22 = 16 (1) 2m+4y+z=15 (2) 2m+3y+5z = 23 (3) Enter the exact answer as an ordered triple, (m, y, z). Hint: There are multiple ways to solve this system of equations. - A strategy is to eliminate one of the variables and end up with 2 equations in 2 variables. . One way to do that is to begin with equation 2 to get z = 15 2 a: 4 y. . Then substitute 15 2 a: 4 y for z in equations 1 and 3. . You now have 2 equations (the modied equations 1 and 3) in 2 variables (a: and y). . Solve this smaller system for a: and y and then use z = 15 2 a: 4 y to calculate z