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A108 mL steam (water vapor) sample initially has a mass of 77.96 mg at a pressure of 995 mmHg and a temperature of 125 C. The system is cooled. Calculate the amount of heat that will be released by the system if the steam which starts out at 125 C all transforms into liquid water at 59.0 C. Given Constant: The heat of vaporization of water at 100.0 C is 40.7 kJ/mol The heat of fusion of water at 0.0 C is 6.02 kJ/mol. Specific heat capacities: solid water (ice): q=2.09 J/g C liquid water: q = 4.184 J/g C water vapor (steam): q = 1.84 J/g C ) 159 J of heat released O 17.1 J of heat released 225 J of heat released ) 193 J of heat released