solve this

Google Chrome File Edit View History Bookmarks Profiles Tab Window Help GO Q 8 Tue Nov 18 9:20 AM Home | myLU X LU HW: 5.1 - 5.3 Assignment ALEKS - Jacob Cascio - HW: G 20 www-awu.aleks.com/alekscgi/x/Isl.exe/10_u-IgNslkr7j8P3jH-li-WSp540wncg8Tof4a5q5fmgWG31RYRVbH21fpfsxjJ... @ * Co C Finish update : homework-help/thread/66307970 | Ca | c Finish update : HW: 5.1 - 5.3 Assignment Jacob rom cours Q Al Chat with PDF Upload for Unlocks Expert Help Study Resources v Ask Al Question 30 of 54 (1 point) | Question Attempt: 1 of Unlimited S Espanol 25 26 27 28 29 30 31 32 33 34 35 36 Answer explanation by Al Answer: $11,070 A contestant on The Biggest Loser starts out weighing 315 pounds and loses weight steadily at the rate of 5 pounds per week. DO Step-by-step: Use the linear model T(x) = 4170 + 230x, where x is years after 1980. Part: 0 / 2 . For 2010, x = 2010 - 1980 = 30 Part 1 of 2 . Compute T(30) = 4170 + 230(30) = 4170 + 6900 = 11,070. So, the poverty threshold in 2010 was approximately $11,070. Write a linear function that describes the contestant's weight in terms of weeks. Let x stand for number of weeks since the contest began, and let W (x) be the contestant's weight. A linear function that represents this situation is W (x) =]. Verify with tutor 5 X solve this Answer explanation by Al Answer: 2028 Explanation: . Model: T(x) = 4170 + 230x, where x is years after 1980. We want the first year when T(x) 15000. Solve: 4170 + 230x 15000 230x 10830 x 10830/230 = 47.087 The first whole number of years after 1980 exceeding this is x = 48. Year = 1980 + 48 = 2028. So the poverty threshold will pass $15,000 in 2028. Ask Al your follow up question. Do not enter personal information. Attach image Upload doc Skip Part Check Save For Later Submit Assignment 2025 McGraw Hill. Terms of Use | Privacy Center | Accessibility Proposal Classical Minecraft 35 54,863 NOV 2 N 4 exec 18 utv O DOCX