Question: solve this(A[0...n-1]) for i = 0 to n-2 do for j = i+1 to n-1 do if A[i] = A[j] return false ** return true

solve this(A[0...n-1])

for i = 0 to n-2 do

for j = i+1 to n-1 do

if A[i] = A[j] return false **

return true

(a) What does this algorithm compute?

(b) Express how many times the marked (**) operations is executed. Express as a sum and solve in terms of n.

(c) What is the efficiency class of this algorithm?

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