Solve triangle ABC if ^A = 43.2°, a = 188.4, and b = 248.6.sin B =(round answer to 5 decimal places)There are two possible angles B between 0 and 180" with this value for sine. Find the two angles, and report them so that ^B? is the acute angle.^B1= and ^B? =(round these and all remaining answers to 1 decimal place)Thus, two triangles satisfy the given conditions: triangle A?B?C? and triangle A2B2C2.Solve the first triangle: A?B?C?^C? and c? =Solve the second triangle: A? B?C2^C?= and c2 =