Question: solve using 4th order runge kutta method, interval is (1,2) and h is 0.1. note that xn = 1 and yn = 2 for the

solve using 4th order runge kutta method, interval is (1,2) and h is 0.1. note that xn = 1 and yn = 2 for the initial values
solve using 4th order runge kutta method, interval is (1,2) and h

dy = x-2 (sin(2x) - 2xy); y(1) = 2 = dx =

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