Question: Solve using back substitution. X1 3x2 + 4x3 = 7 2 -5x3 = 2 x1 5x2 + 2x3 = 10

Solve using back substitution.


X1 3x2 + 4x3 = 7 2 -5x3 = 2 x1 5x2

X1 3x2 + 4x3 = 7 2 -5x3 = 2 x1 5x2 + 2x3 = 10

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