SOLVE USING MATLAB

A cannon is fired on level ground. Allow the user to input the initial total velocity v0 and initial elevation angle theta in degrees (0 degrees = cannon fired horizontally, 90 degrees = cannon fired straight up). Output the x and y position of the cannon ball from 0 seconds to 1 second in increments of 0.1 seconds in a nice table format with three columns. Your output should look similar to the following table:

time x y

0 0 0

0.1 1.21 2.28

0.2 2.42 4.18

(and so on until t = 1.0)

Remember that theta should be in radians for use in trigonometic functions, not degrees. Assume the initial position is (x,y) = (0,0). The vertical acceleration due to gravity is -9.8 m/s2.