Solve using MATLAB, please provide screenshots and explanations/comments where necessary, thanks in advance.

2. Cross Product and Moment of a Force In this problem, you will derive the formula for the cross product using the symbolic toolbox, and then use the cross product to find the moment of a force. A vector in three-dimensional space represents both a magnitude and a direction. A vector A is represented as A = [Ax Ay Az] where Ax, Ay, and Az represent the magnitude of the vector in the x, y, and z directions. The moment of a force is the cross product of two vectors r and F and is given by: moment of a force = cross(r, F) Here, r is the vector representing the distance of the pivot point from the point where the force is applied, and F is the force vector. To calculate the force vector, you need to find the components of the force in the x, y, and z directions: (a) Given two vectors A = [ax ay az] and B = [bx by bz], write a program to find the formula for the cross product of A and B (in terms of ax, ay, bx, by, etc.) by calling the function cross(A, B). (b) A force of F lbf is applied vertically to the lever at point A (as shown) when the lever is positioned at an angle of degrees: d feet Flbf Because the force is applied in the negative-y direction, the components of force are 0 in the x and z directions. Therefore, the force vector F is [0 -F 0). The vector r is dcos() in the x-direction and dsin ) in the y direction. Therefore, r=[dcos(O) dsin ) 0] Then, the moment of the force about the pivot point is calculated as cross(r, F). Using the symbolic toolbox, write a program to: i. Determine the symbolic expression for the moment about the pivot point when a horizontal force is applied. 11. Substitute the values F = 200 lb, d = 24 inches, and 0 = 45 degrees for the following: Determine the horizontal force at A that produces the same moment as (vertical) F. Determine the location where a force F2 = 300 lb can produce the same moment as F. Repeat for an angle of 30 degrees