Question: Solving for ( k ): [ k = frac{0.017 times 9.81 times 22.0}{0.5 times (0.080)^2} ] [ k approx frac{3.67362}{0.0032} ] [ k approx 1148.63

Solving for ( k ): [ k = \frac{0.017 \times 9.81 \times 22.0}{0.5 \times (0.080)^2} ] [ k \approx \frac{3.67362}{0.0032} ] [ k \approx 1148.63 , \text{N/m} ]\

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Solving for ( k ): [ k = \frac{0.017 \times 9.81 \times 22.0}{0.5 \times (0.080)^2} ] [ k \approx \frac{3.67362}{0.0032} ] [ k \approx 1148.63 , \text{N/m} ]\

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