Question: Someone please help me in part D and E for the first picture and part C,D for the second picture. I have tried several answers,

Someone please help me in part D and E for the first picture and part C,D for the second picture. I have tried several answers, but they are still wrong.

Someone please help me in part D and E for the firstpicture and part C,D for the second picture. I have tried several

Use the MacLaurin series for sin( ) to find a power series representation for the following function and interval of convergence- f(I) = re-I [A] Find a power series representation for f(). Note that ( - 1)" is already included in the series and doesn't need to be included in your inputted answer. f(z) = > (-1)" I ( 7 + 7 ) n=0 [B] Find tharinteval of convergence for the power series above: Interval of convergence: (-00.00 [C] Find a power series expression for the following (n +8) (n + 8)n! [D] Use the first three terms of the power series derived from part C to evaluate the following. Round y answer to four decimals. 3.5 D'e do= [E] From your result from part D find a bound on the error for your estimate of me " dr. While there could be several error bounds for a seri s that converge use the error bound that was discussed for convergent alternating series. Round your answ lawyer to four decimals.Use the MacLaurin series for sin(c ) to find a power series representation for the following function and the interval of convergence. f(I) - I' cos (5x) [A] Find a power series representation for f( ). Note that ( - 1)" is already included in the series and doesn't need to be included in your inputted answer. f(I) = E (-1)" 52n . ( 12n+9) n=0 (2n)! [B] Find the inteval of convergence for the power series above: Interval of convergence: ( -00,00 ) [C) Use the first three terms of the power series derived from part A to evaluate the following. Round your answer to four decimals. 1.35 cos (5 - 1.359) 514007.3597 [D] From your result from part C find a bound on the error for your estimate of 1.35 cos (5 - 1.359) While there could be several error bounds for a series that converge use the error bound that was discussed for a convergent alternating series.-Round your answer to four decimals. error -15901027.28

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