Question: Someone proposes the following algorithm for performing fast exponentiation, to be faster than iterative exponentiation, implemented in C++: // @x: a number. // @n: a

 Someone proposes the following algorithm for performing fast exponentiation, to be

Someone proposes the following algorithm for performing fast exponentiation, to be faster than iterative exponentiation, implemented in C++: // @x: a number. // @n: a positive integer. // @return x^n. == long Power (long x, unsigned int n) { if (n 0) return 1; if (n == 1) return x; if (n % 2 0) return Power (x * x, n / 2); else return x Power (x * x, n / 2); } Does it work? What is its time complexity? == *

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