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function [ y ] = MyExp( x,n )
%
% Function: y = MyExp( x, n )
% Uses the Taylor series expansion for exp(x), with n terms,
% to compute an approximation to exp(x).
%
% Input: x = vector containing values at which the exponential is
% to be computed
% n = number of terms in the Taylor series
%
% Output: y = vector, having same length as x, containing exp(x)
% values
%
term = ones(size(x));
y = ones(size(x));
for k = 1:n
term = term .* (x/n);
y = y + term;
end

end 

Answer rating: 100% (QA)

There are a few issues with this code The calculation of the Taylor series is incorrect The term var... View the full answer