Question: Sometimes, the constraints in optimization problems look like sub(a,1)sub(x,1)+...+sub(a,n)sub(x,n)c, assuming n decision variables. To clarify, suppose that the sub(x,i)s represent dollars, and for some reason,

Sometimes, the constraints in optimization problems look like sub(a,1)sub(x,1)+...+sub(a,n)sub(x,n)c, assuming n decision variables. To clarify, suppose that the sub(x,i)s represent dollars, and for some reason, they seem to work better with thousands of dollars. Let the sub(y,i)s be the new variables representing thousands of dollars. How should the constraint above be restated? under()sub(a,i)sub(y,i)=1000c sub(a,1)sub(y,1)+...+sub(a,n)sub(y,n)=frac(c,1000) frac(sub(a,1),1000)sub(y,1)+...frac(sub(a,n),1000)sub(y,n)=c sub(a,1)sub(y,1)+...+sub(a,n)sub(y,n)=1000c

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Mathematics Questions!