Question: # # SQ 0 5 std bool ok ( int * q int i ) { ( int p = 0 p < i

"
#
#SQ05
std
bool ok (int * q int i){
(int p =0 p < i p++)
((q[p]== q[i])||( abs(q[p]-q[i])==i - p))
}
void (int * a int n){
int =0
cout<<""""<<++count< for(int i=0;i for(int j=0;j if(j == a [i]) cout<<""Q""
<<"""";
cout<}
cout<}
(int* q int i int n){
(i == n){
(q n)
}
{
(int j =0 j < n++j){
q[i]= j
( OK (q, i))(q, i+1, n)
}
}
}// recursive n-queens
int main(){
int q[8];
(q,0)
}
: N 1"N " N NxN "" N Queens 8x8101D "

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