Question: Standard deviation is calculated as: E(X^2) = Sum (x^2*P(X=x)) =0^2*0.12 + 1^2*0.18 +2^2*0.30 +3^2*0.15+ 4^2*0.1 +5^2*0.10+6^2*0.05. =0+0.18+0.12+1.35+1.6+2.5+1.8 =.8.63 V(X) = E(X^2) -(E(X)) ^2 = 8.63

Standard deviation is calculated as: E(X^2) = Sum (x^2*P(X=x)) =0^2*0.12 + 1^2*0.18 +2^2*0.30 +3^2*0.15+ 4^2*0.1 +5^2*0.10+6^2*0.05. =0+0.18+0.12+1.35+1.6+2.5+1.8 =.8.63 V(X) = E(X^2) -(E(X)) ^2 = 8.63 - 2.43^2 =2.7251 Standard deviation = sqrt(V(X)) =1.65. is this correct

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