Question: State a good candidate for loop invariant. No proof required. Function to check if a number is prime boolean isPrime ( int n ) Check

State a good candidate for loop invariant. No proof required. Function to check if a number is prime boolean isPrime(int n) Check numbers from 2 to the square root of n for (int i =2 ; Math.sqrt(n); ) If is divisible by , it's not prime if ( xi==0) return false; If no divisor is found, is prime return true

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