Question: static boolean search ( int [ ] a , int x ) { int n = a . length; for ( int h = n;

static boolean search(int[] a, int x){
int n = a.length;
for (int h = n; h >0; h /=2){
for (int i = n-1; i >=0; i-= h){
if (a[i]== x){
return true;
}
}
}
return false;
} Argue that the worst case running time of search is directly proportional to the number
of times the if (a[i]== x) test is checked in the worst case

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