static friction is $0\mathrm{.}6$ with a normal force of $100$ N$."$od en$"$The frictional force is $40$ N since the coefficient of kinetic friction is $0\mathrm{.}4$ and there is a normal force of $100$ N$.""$The frictional force is $35$ N since the box will not be moving and the frictional force will cancel out the applied force of $35$ N$."$O$"$It is $40$ N for the kinetic frictional force and $60$ N for the static frictional force.The normal force is $100$ N and the coefficient of kinetic friction is $0\mathrm{.}4,$ giving $40$ N for the kinetic friction. Similarly, for the static frictional force it is $60$ N since it has a coefficient of static friction of $0\mathrm{.}6.$"With which of these students do you agree with, if any? Explain.