Question: Statistics: For questions 1-5: A single replicate 2 4 experiment is designed. The experiment has factors A, B, C, and D, each of which can

Statistics:

For questions 1-5:

A single replicate 24experiment is designed. The experiment has factors A, B, C, and D, each of which can be set to +1 or -1. We conduct a single replicate of this experiment, collecting the response for each possible combination of factor settings.

Statistics:For questions 1-5:A single replicate 24experiment is designed. The experiment has factorsA, B, C, and D, each of which can be set to+1 or -1. We conduct a single replicate of this experiment, collectingthe response for each possible combination of factor settings. Treatment Factor AFactor B Factor C Factor D Response (1) - 1 - 116.83 - 1 - 1 - 1 17.20 - 19.29 - 118.94 - 1 14.72 14.25 bc - - 8.04 bed - 9.87a - 18.93 ad 17.33 ac - 1 18.15 acd 17.77 ab14.21 abd 15.64 abc - 1 - 9.33 abcd - 9.26Question 9Coefficient B12 O -9.246 O -8.829 O -7.222 O -5.975 O -3.256O 1.077 O 1.301 O 4.131 0 5.579 O 7.431Question 10 1pts Compute the residuals for this model; which of the following normalprobability

Treatment Factor A Factor B Factor C Factor D Response (1) - 1 - 1 16.83 - 1 - 1 - 1 17.20 - 19.29 - 1 18.94 - 1 14.72 14.25 bc - - 8.04 bed - 9.87 a - 18.93 ad 17.33 ac - 1 18.15 acd 17.77 ab 14.21 abd 15.64 abc - 1 - 9.33 abcd - 9.26Question 9 Coefficient B12 O -9.246 O -8.829 O -7.222 O -5.975 O -3.256 O 1.077 O 1.301 O 4.131 0 5.579 O 7.431Question 10 1 pts Compute the residuals for this model; which of the following normalprobability plots show these residuals? O 2.0 1.5 1.0 . 0.5 Quantiles 0.0 ... -0.5 . -1.0 -1.5 -2.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 Residuals O 2.0 1.5 1.0 0.5 Quantiles 0.0 .. -0.5 -1.0 -1.5 -2.0 -1.5 -1.0 -0.5 0.0 0.5 1.0 1.5 Residuals\fTreatment Factor A Factor B Factor C Factor D Response (1) - 1 - 1 - 1 - 1 - 6.13 - 1 - 1 - 1 1 - 5.09 C - 1 - 1 - 4.20 cd - 1 - 3.82 b - 1 = 1 - 1 - 22.52 bd -1 = 1 1 - 22.27 bc - 1 - 1 - 20.57 - - bed - 1 1 - 22.67 a - 1 - 1 - 1.86 ad - 1.27 ac - 1 - 1 - 2.37 acd - 1 1 - 2.77 ab - 1 - 4.08 abd = 1 1 - 1.95 abc - 1 - 3.29 abcd 1 - 1.65

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