Stats 119, Please provide explanation for future note. Please and thank you :)

The data show the chest size and weight of several bears. Find the regression equation, letting chest size be the independent (x) variable. Then find the best predicted weight of a bear with a chest size of 51 inches. Is the result close to the actual weight of 615 pounds? Use a significance level of 0.05. Chest size (inches) 47 46 49 50 38 48 Weight (pounds) 487 496 546 518 397 510 Click the icon to view the critical values of the Pearson correlation coefficient r. What is the regression equation? y = [+x(Round to one decimal place as needed.) What is the best predicted weight of a bear with a chest size of 51 inches? The best predicted weight for a bear with a chest size of 51 inches is pounds. (Round to one decimal place as needed.) Is the result close to the actual weight of 615 pounds? O A. This result is close to the actual weight of the bear. O B. This result is very close to the actual weight of the bear. O C. This result is not very close to the actual weight of the bear. O D. This result is exactly the same as the actual weight of the bear.i Critical Values of the Pearson Correlation Coefficient r X Critical Values of the Pearson Correlation Coefficient r n 0 = 0.05 0 = 0.01 NOTE: To test Ho: p= 0 0.950 0.990 against Hy: p #0, reject Ho 0.878 0.959 if the absolute value of r is 0.811 0.917 greater than the critical 0.754 0.875 value in the table. 0.707 0.834 0.666 0.798 10 0.632 0.765 11 0.602 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 18 0.468 0.590 19 0.456 0.575 20 0.444 0.561 25 0.396 0.505 30 0.361 0.463 35 0.335 0.430 40 0.312 0.402 45 0.294 0.37850 0.279 0.361 60 0.254 0.330 70 0.236 0.305 80 0.220 0.286 90 0.207 0.269 100 0.196 0.256 n 0 = 0.05 0 = 0.01