Step $1$: $4Fe{S}_2(s)+11O_2(g)2F{e}_2{O}_3(s)+8S{O}_2(g)$

Step $2$: $F{e}_2{O}_3(s)+3CO(g)3C{O}_2(g)+2Fe(s)$

Extraction of $Fe(s)$ from pyrite, $Fe{S}_2,$ is a two$-$step process, as represented above. The maximum amount of $Fe(s)$ that could be extracted from $120$ grams of $Fe{S}_2($molar mass $120\frac{g}{m}ol)$ is approximately

$($A$)28$ grams

$($B$)56$ grams

$($C$)84$ grams

$($D$)112$ grams