Step $2$

Let's set $up$ the integral that will give $us$ the area $of$ the region that $is$ bounded between $x=18-2y^2$ and

$x=2y^2-18.$

When $we$ set $up$ the integral, should $we$ integrate with respect $toxor$ with respect $toy?$

Since the height $of$ the typical approximating rectangle $is$ parallel $to$ the $x-$axis, $we$ should integrate

with respect $tox.$

Since the narrow width $of$ the typical approximating rectangle $is$ parallel $to$ the $x-$axis, $we$ should

integrate with respect $tox.$

Since the narrow width $of$ the typical approximating rectangle $is$ parallel $to$ the $y-$axis, $we$ should

integrate with respect $toy.$

Since the height $of$ the typical approximating rectangle $is$ parallel $to$ the $y-$axis, $we$ should integrate

with respect $toy.$

The points $of$ intersection will give $us$ the indices $of$ integration. What are the indices $of$ integration? Enter

your answers $as$ a comma separated list.

Which $of$ the following integrals represents the area $of$ the region bounded between $x=18-2y^2$ and

$x=2y^2-18?$

${\displaystyle \underset{-18}{\overset{18}{}}}((x^2-3^2)-(3^2-x^2))dx$

${\displaystyle \underset{-3}{\overset{3}{}}}((2y^2-18)-(18-2y^2))dy$

${\displaystyle \underset{-18}{\overset{18}{}}}((3^2-x^2)-(x^2-3^2))dx$

${\displaystyle \underset{-3}{\overset{3}{}}}((18-2y^2)-(2y^2-18))dy$