Question: Step 4 : Click Play and keep an eye on the velocity and acceleration boxes. How does the velocity change as the time and position

Step 4: Click Play and keep an eye on the velocity and acceleration boxes.
How does the velocity change as the time and position change?
Your answer:
How does the acceleration change as the time and position change?
Your answer:
Step 5: Click the Reset All button. Type -10 in the position box, 0.1 in the velocity box, and 0.2in the acceleration box. Click Play and observe the three graphs carefully. Pause the motion between the 8 and 10 meter marks, before the man hits the wall.
Step 6: Click the button to minimize the velocity and acceleration graphs. Is the position versus time graph a straight line or a curve?
Your answer:
Step 7: Minimize the position and click on the button to expand the velocity graph. Is the velocity versus time graph a straight line or a curve?
Your answer:
Step 8: Use the playback feature to find the velocity at time 4 s and at time 8 s. When you drag the vertical scanning bar across the graph, the time is displayed below the simulation menu (next to the man), and the velocity is displayed in the velocity box.
v (at t =4s)=
v (at t =8s)=
Calculate the average acceleration. Show all your work below.
The equations of motion for an object moving along a straight line (one dimensional motion) with constant acceleration in this case would be:
(1)
(2)
(3)
Step 9: Use the equation (2) above to find the position xf at time t =10s. Show all your work below. Remember that the initial position xi =-10 m, initial velocity vi =0.1 m/s and you know the acceleration from step 5 above.
Step 10: Now go back to the position graph and use the playback feature to find the position at time t =10s.
Position (at t =10s)=
Take a screenshot of your graph along with the position measurement at t =10s, and paste it in the space below.
Step 11: Click the Reset All button. Type -10 in the position box, 8 in the velocity box, and -1.8 in the acceleration box. Click Play and observe the three graphs carefully as the man goes in the positive direction and returns back towards the negative direction. Pause the motion between the -8 and -10 meter marks on the way back, before the man hits the wall on the left end.
Use the playback feature to find time and position when the man stops during the motion.
t (man stops)=
x (man stops)=
Take a screenshot of your graph along with the position measurement when the man stops, and paste it below.
Also find the time and velocity when the man passes through the origin. If the man goes through the origin twice, write both values separated by a comma.
t (at x =0)=
v (at x =0)=
Step 12: Lets make a prediction. Suppose that your car is at rest, so vi =0 m/s. You press the gas pedal and the cars acceleration is constant at 1.5 m/s2.
How long would it the car take to travel 25 m from the starting point? Show all your work below. (Remember you can use the three equations of motion of the last page as long as the acceleration is constant.)
t (25 m)=
What is the cars velocity when it reaches the 25 m mark? Show all your work below.
v (25 m)=

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