Question: stone was thrown vertically upwards from a balcony that is 32 feet above the ground with an initial velocity of 16 ft/sec. Assume that the
stone was thrown vertically upwards from a balcony that is 32 feet above the ground with an initial velocity of 16 ft/sec. Assume that the height h(t) of the stone at time t (in seconds) follows the general position of a free-falling object h(t) = 16t2 +v0t+h0 where v0 is the initial velocity and h0 is the initial height.
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