Strip a dilute amount of hydrogen sulfide from water using air. 9 5°?- The system is operated warm and at lower pressure to increase the removal of hydrogen sulfide. The stripper is at 45 "C and 0.98 atm. The inlet liquid mole fraction is 7.00E-6 hydrogen sulfide. Inlet liquid flow rate is 100 kg moles/hr. We desire to remove 98% of the hydrogen sulfide. The inlet gas has y=0.00. Inlet gas flow rate is 0.20 kg moles/hr. You can assume that total liquid and gas flow rates are constant. Equilibrium data Is: Partial pressure of hydrogen sulfide (atm) = 745 x And x is the mole fraction of hydrogen sulfide in water. (Perry, 7th ed., p.2- 127) In this concentration range, how do the mole fractions x and y compare to mole ratios X and Y?

 How does this simplify the problem? 

Calculate the outlet gas and liquid mole fractions of hydrogen sulfide. 

Calculate the number of equilibrium stages required using a McCabe- Thiele diagram lf LN = M x (W)max, find the multiplier M (M<1).

Why would this column be difficult to operate?

Answer rating: 100% (QA)

Solution The problem can be simplified by noting that the mole fractions x and y are small which all... View the full answer