struct lnode $\{$

struct lnode $*$prev;

struct lnode $*$next;

char first;

char $*$word;

int length;

$\}$;

We decide to look at the node in gdb and see the following:

$($gdb$)$ x$/4$xg $0$x$555555554774$

$0$x$555555554774$: $0$x$6$f$722031363253430$x$6$c$65480021736$b$63$

$0$x$555555554784$: $0$x$3$b$031$b$0100216$f$6$c $0$x$000000060000003$c

$($gdb$)$ x$/14$xg $rsp

$0$x$7$fffffffea$00$: $0$x$00007$fffffffeb$580$x$00000001756$e$6547$

$0$x$7$fffffffea$10$: $0$x$00007$fffffffea$400$x$0000000000000000$

$0$x$7$fffffffea$20$: $0$x$00000000000000430$x$0000555555554774$

$0$x$7$fffffffea$30$: $0$x$000000000000000$c $0$x$000055555555473$d

$0$x$7$fffffffea$40$: $0$x$00000000000000000$x$00007$fffffffea$10$

$0$x$7$fffffffea$50$: $0$x$00000000000000480$x$0000555555554781$

$0$x$7$fffffffea$60$: $0$x$00000000000000060$x$2248$a$3$a$88$ddbb$600$

Fill$-$in the following blanks for the node starting at address $0$x$7$fffffffea$10.$

$-$ The field length is stored at address Blank $1($copy the value and paste it here including $0$x$)$

$-$ The field next is stored at address Blank $2($copy the value and paste it here including $0$x$)$

$-$ The value stored in the field prev is Blank $3($copy the value and paste it here including $0$x$)$

$-$ the second ASCII character referenced by word is Blank $4($you can use an ASCII table$)$

$-$ The value stored in the field length is Blank $5($number in decimal$)$